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Answer :
The second container will hold about 13 cubic inches more than the first container.(Option B)
To compare the volumes of the two cone-shaped containers, we can use the formula for the volume of a cone:
[tex]\[ V = \frac{1}{3} \pi r^2 h \][/tex]
For the first container:
- Diameter = 6 in. (so, radius [tex]\( r_1 = \frac{6}{2} = 3 \)[/tex] in.)
- Height = 4 in.
[tex]\[ V_1 = \frac{1}{3} \pi (3)^2 \times 4 = \frac{1}{3} \pi \times 9 \times 4 = 12 \pi \][/tex]
For the second container:
- Radius = 4 in.
- Height = 3 in.
[tex]\[ V_2 = \frac{1}{3} \pi (4)^2 \times 3 = \frac{1}{3} \pi \times 16 \times 3 = 16 \pi \][/tex]
Now, let's compare the volumes:
[tex]\[ V_1 = 12 \pi \][/tex]
[tex]\[ V_2 = 16 \pi \][/tex]
Since [tex]\( \pi \)[/tex] is the same in both volumes, we can compare them directly:
[tex]\[ V_2 - V_1 = 16 \pi - 12 \pi = 4 \pi \][/tex]
Now, let's calculate the numerical value of [tex]\( 4 \pi \)[/tex]: [tex]\[ 4 \pi \approx 12.5664 \][/tex]
So, the second container will hold about 12.5664 cubic inches more than the first container.
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Rewritten by : Barada
Answer:
I would say for 1. would be A
And i think... that 2. is 3 i'm not sure that's all i really know
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