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Answer :
For this case, the first thing we must take into account are the following conversions:
[tex] 1 gallon = 3.79 liters [/tex]
[tex] 1 hour = 60 minutes [/tex]
Then, we apply the conversions step by step.
To transform to liters per minute we have:
[tex] (20\frac{gal}{min}) * (3.79\frac{L}{gal}) = 75.8\frac{L}{min} [/tex]
Then, we convert the result in liters per hour.
We have then:
[tex] (75.8\frac{L}{min}) * (60)\frac{min}{h} = 4548\frac{L}{h} [/tex]
Answer:
the rate in liters per hour is:
4548
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Rewritten by : Barada
Hello,
[tex] \dfrac{20 \ gallons}{1\ min} = \dfrac{3.79*20\ l}{ \frac{1}{60}\ h}\\
=\dfrac{3.79*20*60\ l}{ 1\ h } =4548\ l/h[/tex]
[tex] \dfrac{20 \ gallons}{1\ min} = \dfrac{3.79*20\ l}{ \frac{1}{60}\ h}\\
=\dfrac{3.79*20*60\ l}{ 1\ h } =4548\ l/h[/tex]