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Mark’s school is selling tickets to the annual dance competition.

On the first day of ticket sales, the school sold 4 senior tickets and 4 child tickets for a total of $68.

On the second day, the school took in $120 by selling 12 senior tickets and 5 child tickets.

Find the price of a senior ticket and a child ticket.

Answer :

The price of one adult ticket is 5 and price of one child ticket is 12.

Step-by-step explanation:

Let,

Price of one senior ticket = x

Price of one child ticket = y

According to given statement;

4x+4y=68 Eqn 1

12x+5y=120 Eqn 2

Multiplying Eqn 1 by 3

[tex]3(4x+4y=68)\\12x+12y=204\ \ \ Eqn\ 3[/tex]

Subtracting Eqn 2 from Eqn 3

[tex](12x+12y)-(12x+5y)=204-120\\12x+12y-12x-5y=84\\7y=84\\[/tex]

Dividing both sides by 7

[tex]\frac{7y}{7}=\frac{84}{7}\\y=12[/tex]

Putting y=12 in Eqn 1

[tex]4x+4(12)=68\\4x+48=68\\4x=68-48\\4x=20[/tex]

Dividing both sides by 4

[tex]\frac{4x}{4}=\frac{20}{4}\\x=5[/tex]

The price of one adult ticket is 5 and price of one child ticket is 12.

Keywords: linear equation, elimination method

Learn more about elimination method at:

  • brainly.com/question/12773544
  • brainly.com/question/1279756

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