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Robs number is equal to twice bobs number, cobs number is eight times larger than two less than bobs number, the sum of robs number and cobs number is 22, what are each of their numbers?

Answer :

By setting up algebraic equations based on the problem's details and solving them, we find that Bob's number is 3.8, Rob's number is 7.6, and Cob's number is 14.4.

The question involves solving a set of algebraic equations to find the numbers corresponding to Rob, Bob, and Cob. Let's denote Bob's number as B. According to the question, Rob's number (R) is twice Bob's number, so R = 2B. Cob's number (C) is eight times larger than two less than Bob's number, which translates to C = 8*(B-2). The sum of Rob's and Cob's numbers is 22, giving us the equation R + C = 22. Substituting the expressions for R and C in terms of B into this last equation allows us to solve for B, and subsequently find R and C.

First, substitute the expressions for R and C: 2B + 8*(B-2) = 22. This simplifies to 10B - 16 = 22, which further simplifies to 10B = 38, giving B = 3.8. Using B's value, we find R = 2*3.8 = 7.6 and C = 8*(3.8-2) = 8*1.8 = 14.4.

Therefore, Bob's number is 3.8, Rob's number is 7.6, and Cob's number is 14.4. This solution was obtained by translating the words of the problem into equations and then solving the system of equations step by step.

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Rewritten by : Barada

B=B
R=2B
C=8(B-2)=8B-16
R+C=22
(2B)+(8B-16)=22
B=3.8
R=7.6
C=14.4