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Answer :
187 jumping jacks in total
60 for each of the first 2 days
y=number of jumping jacks on day 3
187=y+2(60)
187-2(60)=y
Solution: B. y=187-(60×2)
60 for each of the first 2 days
y=number of jumping jacks on day 3
187=y+2(60)
187-2(60)=y
Solution: B. y=187-(60×2)
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