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Answer :
Answer:
120 kpa is the answer
Explanation:
As the pressure on a liquid is changed from 100 kPa to 120 kPa, the temperature at which the liquid will boil
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This question can be solved using Antoine equation, based on a correlation of three parameters A, B and C. The vapor pressure at 105 ∘ C is 120 kPa
What is Antoine equation?
The Antoine equation describes the relationship between the temperature and the vapor pressure of pure substances. In other words, it is an equation used to obtain the value of the vapor pressure as a function of temperature for pure components, and is based on a correlation of three parameters A, B and C.
The Antoine equation is:
[tex]p=10^{A-\frac{B}{C+T} }[/tex]
where:
P is the vapor pressure of water, usually in mmHg.
T is the water temperature in celsius.
A, B and C are the Antoine constants for water. The values of A, B and C depend on the units used for the vapor pressure and the temperature range at which the correlation was obtained.
In this case, since the temperature is, the temperature range of interest from 99 to 374 ° C. Then the parameters will have the following values: A = 8.14019, B = 1810.94 and C = .244.485
Substituting the values
[tex]p=10^{ 8.14019-\frac{1810.94}{244.485+ 105 ° C} }[/tex]
P=908.7641 mmHg÷7.5= 120 kPa
Thus vapor pressure at 105 ∘ C is 120 kPa
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