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Answer :
Final answer:
The toy rocket is in the air for 8 seconds. This is found by setting the equation for its height as a function of time to zero and solving for t.
Explanation:
The toy rocket's height as a function of time is given by the equation h(t) = -16t² + 128t. The rocket is in the air as long as its height h(t) is greater than 0. To find this time, we set the equation to 0 and solve for t, that is, -16t² + 128t = 0. Factoring out a t gives us: t(-16t + 128) = 0. The rocket is at ground level (height 0) at launch time t=0 and when it lands. The landing occurs when -16t + 128 = 0 which simplifies to t = 128÷16 which is 8 seconds.
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Answer:
8 seconds
Step-by-step explanation:
Just use the quadratic equation, but remember, use only positive answer(s). Time can't be negative.
