Answer :

Final answer:

The change in velocity of a 7.3-kg bowling ball when a force of 186 N is applied for 0.40 seconds is calculated using the impulse-momentum theorem, resulting in a change in velocity of 10.21 m/s.

Explanation:

The student is asking about the change in velocity of a bowling ball when a force acts on it for a specific amount of time. This is a classical mechanics problem typically covered in high school physics. The formula that relates force, time, and change in velocity is derived from Newton's second law of motion and the impulse-momentum theorem, which is impulse equals the change in momentum. The impulse is given by the force multiplied by the time during which the force is applied. Here, we will calculate the change in velocity (Δv) using the formula:

Δv = F × t / m

Where:

F is the force applied (186 N),

t is the time the force is applied (0.40 s),

m is the mass of the bowling ball (7.3 kg).

Plugging in the values, we get:

Δv = (186 N) × (0.40 s) / (7.3 kg) = 10.21 m/s

Therefore, the change in velocity of the bowling ball is 10.21 m/s.

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Rewritten by : Barada


As we know that Force = mass * acceleration.
Here a force of 186 N acting on 7.3 kg ball will create acceleration = 186/7.3 = 25.48 m/s2
Also, change in velocity can be found as, acceleration multiplied by time it is acting on object.
Therefore, change in velocity = 24.48 * 0.4 = 10.19 m/s