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Answer :
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[tex]30( \frac{1}{2} x - 2) + 40( \frac{3}{4} y - 4) = \\ [/tex]
[tex](30 \times \frac{1}{2} x) -( 30 \times 2 )+ (40 \times \frac{3}{4} y )- (40 \times 4 )= \\ [/tex]
[tex]15x - 60 + 30y - 160 = \\ [/tex]
[tex]15x + 30y - 220[/tex]
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The correct answer is Option Three .
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