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Answer :
Final answer:
To find the greatest number of food baskets Mrs. Benton can make with 60 cans of beans and 48 cans of tuna, calculate the greatest common divisor, which is 12. Thus, she can make 12 equal baskets.
Explanation:
Mrs. Benton is looking to make the greatest number of food baskets that can be evenly filled with 60 cans of beans and 48 cans of tuna. To find the largest number of baskets she can make, we need to calculate the greatest common divisor (GCD) of 60 and 48. The GCD tells us the largest number that can divide both numbers without leaving a remainder.
First, list the divisors of 60: 1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60.
Then list the divisors of 48: 1, 2, 3, 4, 6, 8, 12, 16, 24, 48.
Find the largest number that appears in both lists. Here, that number is 12.
Therefore, Mrs. Benton can make 12 baskets with an equal number of cans of beans and tuna.
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Answer:
Maximum no. of baskets which Mrs. Benton can make is , 12.
Step-by-step explanation:
According to the question, the greatest number of basket Mrs. Benton can make is, GCD (Greatest Common Divisor) of 60 and 48.
Now,
60 = [tex]2 \times 2 \times 3 \times 5[/tex]
and . 48 = [tex]2 \times 2 \times \times 2 \times \2 \times 3[/tex]
So, the GCD of 60 and 48 is,
[tex]2 \times 2 \times 3[/tex] = 12
So, each basket will have,
[tex]\frac {60}{12}[/tex] = 5 cans of beans and
[tex]\frac {48}{12}[/tex] = 4 cans of tuna
