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Answer :
The surface area of a cylinder to the nearest tenth is 390.8 square feet
Solution:
The surface area of cylinder is given as:
[tex]A=2 \pi rh+2 \pi r^2[/tex]
Where, r is the radius and h is the height
From given,
r = 4.9 feet
h = 7.8 feet
Substituting the values we get,
[tex]A = 2 \times 3.14 \times 4.9 \times 7.8 + 2 \times 3.14 \times 4.9^2\\\\A = 240.0216+150.7828\\\\A = 390.8044 \approx 390.8[/tex]
Thus the surface area of a cylinder to the nearest tenth is 390.8 square feet
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