Middle School

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A 2.26 cm tall object is placed 18.6 cm in front of a convex lens. The focal length is 35.8 cm. How far is the image from the lens?

Answer :

Answer:

the image is -38.7 cm from the lens

Explanation:

We use the lens equation which says

[tex]$\frac{1}{u}+\frac{1}{v}=\frac{1}{f} $[/tex]

where [tex]u[/tex] is the distance to the object, [tex]v[/tex] is the distance to the image, and [tex]f[/tex] is the focal length.

Now, in our case

[tex]u =18.6cm[/tex],

[tex]v= 35.8cm[/tex],

[tex]f = 35.8cm[/tex];

therefore,

[tex]$\frac{1}{18.6}+\frac{1}{v}=\frac{1}{35.8} $[/tex]

[tex]$\frac{1}{v}=\frac{1}{35.8}-\frac{1}{18.6} $[/tex]

[tex]\boxed{v=-38.7cm}[/tex]

where the negative sign indicates that the image is virtual and on the same side of the lens as the object.

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Rewritten by : Barada