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Answer :
Answer:
= 60.16 cm/s or 0.6 m/s
Explanation:
Using the formula for collision;
M1U1 + M2U2 = M1V1 + M2V2
Therefore;
(225 kg)•(98 cm/s) + (198 kg)•(28 m/s) = (225 kg)•v + (198 kg)•(71 cm/s)
22050 kg•cm/s + 5544 kg•cm/s = (225 kg)•v + 14058 kg•cm/s
13536 kg•cm/s = (225 kg)•v
v = 60.16 cm/s
Therefore; the post collision velocity of the 225 kg car is 60.16 cm/s
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