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Answer :
The required number of small apples in one pound is 4.
Given that,
Each bushel of apples weighs 42 lbs. A bushel of large apples contains 84 apples. If a bushel of small apples contains twice as many apples as a bushel of large apples, how many small apples are in 1 lb. of small apples, is to be determined.
What is simplification?
The process in mathematics to operate and interpret the function to make the function or expression simple or more understandable is called simplifying and the process is called simplification.
Here,
Large apples in 1 pound = 84 / 42 = 2
Now, according to the question,
Number of small apples = 2 (number of large apples)
Number of small apples = 2 (2)
Number of small apples = 4
Thus, the required number of small apples in one pound is 4.
Learn more about simplification here: https://brainly.com/question/12501526
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Answer: 4 apples in 1 lb
Step-by-step explanation: There are twice as many small apples as large apples, so multiply 2 × 84 = 168
to find apples per pound, divide the total number of apples, 168, by the weight of the bushel: 42 lbs.
168 /42 = 4 apples/lb
