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Presumably our goal is to show PRQ=SRQ, PQR=SQR and QR=QR for ASA.
A. QR=QR is the reflexive property; things are congruent to themselves, TRUE
B. We need to prove that, but it doesn't have anything to do with the symmetric property.
C. PQ=SQ isn't something we'd need to show for our ASA proof
D. Again, not the symmetric property.
Answer: A
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Rewritten by : Barada
Answer: A. Prove that QR≅QR by the reflexive property.
Step-by-step explanation:
ASA postulate says that if two angles and the included side of a triangle are congruent to two angles and the included side of other triangle then the triangles are said to be congruent.
In the given triangles ΔPQR and ΔSQR
∠PQR ≅∠SQR {given}
∠QRP ≅ ∠QRS {given}
In the figure , the included side of ∠PQR and ∠QRP= QR
The included side of ∠SQR and ∠QRS =OR
So we need to probe QR≅QR by Reflexive property, to prove triangles ΔPQR and ΔSQR are congruent.
