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Answer :
Answer:
Say the first car speed as r
Second car speed will be r-14
Since rate times time equal distance, we have
r + (r -14)2 = 300
2r -14 = 300/2
2r = 150+14
r = 164/2 = 82
Speed of slower car 82-14 = 68 km/hr
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Final answer:
The rate of the slower car is 68 km/h. This was determined by setting up an equation based on the distance traveled and the time taken for the cars to meet, and then solving for the speed of the faster car before calculating the speed of the slower car.
Explanation:
To determine the rate of the slower car, we first need to establish the relationship between the speeds of the two cars. Let's denote the speed of the faster car as V and the speed of the slower car as V - 14 km/h. Since they meet after 2 hours and have traveled a combined distance of 300 kilometers, we can write the equation 2V + 2(V - 14) = 300.
By simplifying this equation, we find:
- 2V + 2V - 28 = 300
- 4V - 28 = 300
- 4V = 328
- V = 82 km/h
Now that we know the speed of the faster car is 82 km/h, we can easily find the rate of the slower car:
- Rate of slower car = V - 14 km/h = 82 km/h - 14 km/h = 68 km/h
