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Answer :
Answer: 12000 kg m/s
Explanation:
According to the Impulse-Momentum Theorem, we have:
[tex]F \Delta t= \Delta p[/tex]
Where:
[tex]F=3000 N[/tex] is the exerted force
[tex]\Delta t=4 s[/tex] is the time interval
[tex] \Delta p[/tex] is the change in momentum or impulse
Then:
[tex](3000 N)(4 s)= \Delta p[/tex]
[tex]\Delta p=12000 kg m/s[/tex] This is the impulse impacted on the object
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