Answer :

The correct relationship between the 4s in the number 4498 is that they are both in the units place, and the second 4 is in the tens place.

To understand the relationship between the digits in the number 4498, let's break it down by place value:

- The first 4 (from the right) is in the units place, which is the [tex]10^0[/tex] place.

- The second 4 (to the left of the first 4) is in the tens place, which is the [tex]10^1[/tex] place.

- The next digit, 9, is in the hundreds place, which is the [tex]10^2[/tex] place.

- The last digit, 8, is in the thousands place, which is the [tex]10^3[/tex] place.

So, the number 4498 can be expanded as:

[tex]4498 = (4 * 10^3) + (4 * 10^2) + (9 * 10^1) + (8 * 10^0)[/tex]

In this expansion, we can see that the first 4 is multiplied by 10^0 (which is 1), and the second 4 is multiplied by [tex]10^1[/tex] (which is 10). Therefore, the second 4 contributes ten times more to the value of the number than the first 4.

To illustrate this further, let's calculate the value contributed by each digit:

- The first 4 contributes [tex]4 * 10^0 = 4[/tex]

- The second 4 contributes [tex]4 * 10^1 = 40[/tex]

- The 9 contributes [tex]9 * 10^2 = 900[/tex]

- The 8 contributes [tex]8 * 10^3 = 8000[/tex]

Adding these up gives us the total value of the number:

4498 = 4 + 40 + 900 + 8000

4498 = 8944

Thus, the relationship between the 4s in the number 4498 is that the first 4 is in the units place and the second 4 is in the tens place, contributing ten times more to the value of the number.

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Rewritten by : Barada

one 4 is in the hundreds place and the other is in the thousands place