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Answer :
Answer:
Part a) The equation of the line is
[tex]y-32=1.8(x-0)[/tex] or [tex]y=1.8x+32[/tex]
Part b) The slope of the line is [tex]m=1.8\frac{\°F}{\°C}[/tex]
Part c) The y-intercept is 32 (For a degrees Celsius equal to zero, the degrees Fahrenheit is equal to 32)
Step-by-step explanation:
Let
x ----> degrees Celsius
y ----> degrees Fahrenheit
we have the points
[tex](0,32),(100,212)[/tex]
Part a) Find the equation of the line
Find the slope m
[tex]m=(212-32)/(100-0)[/tex]
[tex]m=180/100[/tex]
[tex]m=1.8\frac{\°F}{\°C}[/tex]
The equation of the line into slope point form is equal to
[tex]y-y1=m(x-x1)[/tex]
we have
[tex]m=1.8\frac{\°F}{\°C}[/tex]
Point [tex](0,32)[/tex]
substitute
[tex]y-32=1.8(x-0)[/tex] ----> equation of the line into slope point form
[tex]y=1.8x+32[/tex] ---> equation of the line into slope intercept form
Part b) What is the slope of the line?
The slope of the line is [tex]m=1.8\frac{\°F}{\°C}[/tex]
That means
The rate of change of the temperature is 1.8 degrees Fahrenheit by each degree Celsius
Part c) What is the y-intercept of the line?
we have
[tex]y=1.8x+32[/tex] ---> equation of the line into slope intercept form
The y-intercept is 32
The y-intercept is the value of y when the value of x is equal to zero
That means
For a degrees Celsius equal to zero, the degrees Fahrenheit is equal to 32
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