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Answer :
Answer:
680 N
Explanation:
We start by calculating the cheetah's acceleration knowing that goes from rest (0 speed) to 20.1 m/s in 2 seconds:
[tex]a=\frac{v_f-v_1}{t} \\a=\frac{20.1-0}{2} =10.05 \frac{m}{s^2}[/tex]
Now we use the definition of force (F):
[tex]F=m*a\\F=68 kg * 10.05 \frac{m}{s^2} =683.4 N[/tex]
Therefore the force that accelerates the cheetah is 683.4 Newtons which we can round to 680 N to match the fourth choice shown
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