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Answer :
let h(t)= 0 (because when it reaches the ground h=0)
0=-16t^2+116
16t^2=116
divide both sides by 16
t^2= 7.25
square root both sides to find t
t=2.69sec
0=-16t^2+116
16t^2=116
divide both sides by 16
t^2= 7.25
square root both sides to find t
t=2.69sec
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Answer:
2.69 seconds
Step-by-step explanation:
the function for the height and time is:
[tex]h(t)=-16t^2+116[/tex]
when the object collides with the ground, it means that at that moment its height is zero. So we need to solve the equation above for when h(t) equals zero:
[tex]0=-16t^2+116[/tex]
clearing for t:
[tex]-116=-16t^2\\\frac{-116}{-16}=t^2\\ 7.25=t^2\\\sqrt{7.25}=t\\ 2.69=t[/tex]
the object will hit the ground at time 2.69 seconds
