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Complete the synthetic division problem below:

[tex]
2 \, \bigg| \begin{array}{ll}
1 & 5 \\
& -14 \\
\end{array}
[/tex]

What is the quotient in polynomial form?

A. [tex]\(x-5\)[/tex]
B. [tex]\(x+5\)[/tex]
C. [tex]\(x-7\)[/tex]
D. [tex]\(x+7\)[/tex]

Answer :

To solve this synthetic division problem, we'll divide the polynomial by using synthetic division. Here are the steps:

1. Identify the divisor: We have the divisor [tex]\( x - 2 \)[/tex], which means we use the root [tex]\( 2 \)[/tex] in synthetic division.

2. Set up synthetic division: Write down the coefficients of the polynomial. In this case, the polynomial is represented by [tex]\( 1x + 5 \)[/tex]. So, the coefficients are [tex]\( 1 \)[/tex] and [tex]\( 5 \)[/tex].

3. Perform synthetic division:
- Step 1: Bring down the leading coefficient [tex]\( 1 \)[/tex].
- Step 2: Multiply this by the root [tex]\( 2 \)[/tex] and write the result under the next coefficient [tex]\( 5 \)[/tex].
- Step 3: Add the numbers in the second column: [tex]\( 5 + (2 \times 1) = 7 \)[/tex].

The setup looks like this:

```
2 | 1 5
| 2
------------
1 7
```

4. Interpret the result: After carrying out the division, the numbers at the bottom represent the coefficients of the quotient polynomial.

- The [tex]\( 1 \)[/tex] is the coefficient of [tex]\( x \)[/tex].
- The [tex]\( 7 \)[/tex] is the constant term.

5. Write the quotient in polynomial form: The result is [tex]\( x + 7 \)[/tex].

Therefore, the quotient is [tex]\( x + 7 \)[/tex].

Thus, the correct answer is [tex]\( \text{D. } x + 7 \)[/tex].

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