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What is the compressive strength of concrete tested in a standard test cylinder with a 6-inch diameter, which fails under a load of 84,700 lbs?

A. 479 psi
B. 2,247 psi
C. 749 psi
D. 2,997 psi

Answer :

Final answer:

The compressive strength of a concrete cylinder with a diameter of 6 inches, which fails under a load of 84,700 lbs, is 2,997 psi.

Explanation:

The compressive strength of concrete can be determined through the formula P = F/A, where P is the compressive strength, F is the force applied, and A is the area of the subjected surface. In this case, the load (F) is 84,700 lbs. The area of the cylinder (A) can be calculated using the formula for the area of a circle which is πD²/4, where D is the diameter of the cylinder, which is given as 6 inches (0.5 feet).

Substituting the given values into the formula, we get P = 84,700 lbs/(π×(0.5ft)²). Solving this equation yields us 43,227 lb/ft².

If you require the compressive strength in psi (pounds per square inch), 1 lb/ft² is equivalent to 0.00694 psi. Therefore, the compressive strength of the concrete is approximately 2,997 psi. Hence, option D. 2,997 psi is the correct answer.

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