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The length of a rectangle is five times its width. If the perimeter of the rectangle is 120 ft, find its length and width.

Answer :

We know that the length of the rectangle is five times its width. Let's say the width is "w" feet. So, the length would be 5w feet.

Now, we can use the formula for the perimeter of a rectangle, which is 2(length + width), and set it equal to 120 feet.

2(5w + w) = 120

Simplifying the equation:

2(6w) = 120

12w = 120

Dividing both sides by 12:

w = 10

So, the width of the rectangle is 10 feet. Since the length is five times the width, the length would be 5 * 10 = 50 feet.

Therefore, the length of the rectangle is 50 feet and the width is 10 feet.

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Rewritten by : Barada

Answer:

Width: 10

Length: 50

Step-by-step explanation:

I'm going to use the letters W, L, and P to represent Width, Length, and Perimeter.

L = 5W (length is equal to five times the width)

P = 2L + 2W (perimeter is equal to double the width added with double the length)

120 = 2(5W) + 2W (plug in 120 and 5W into the equation and distribute)

120 = 12W (Next step is to divide 120 by 12)

W = 10 (The answer is 10)

Now let's plug it into our first equation...

L = 5(10)

L = 50

There is your answer... hope that helped! :)