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Answer :
Certainly! When calculating the force of gravity acting on an object, we use the formula:
[tex]\[ F = m \times g \][/tex]
Where:
- [tex]\( F \)[/tex] is the force of gravity.
- [tex]\( m \)[/tex] is the mass of the object.
- [tex]\( g \)[/tex] is the acceleration due to gravity.
In this scenario:
- The mass ([tex]\( m \)[/tex]) of the object is 120 kg.
- The acceleration due to gravity ([tex]\( g \)[/tex]) on the moon is approximately 1.63 meters per second squared (m/s²).
Using the formula:
[tex]\[ F = 120 \ \text{kg} \times 1.63 \ \text{m/s}^2 \][/tex]
[tex]\[ F = 195.6 \ \text{N} \][/tex]
Therefore, the correct answer is:
C) 196 N
This is the force of gravity acting on the 120 kg object on the moon.
[tex]\[ F = m \times g \][/tex]
Where:
- [tex]\( F \)[/tex] is the force of gravity.
- [tex]\( m \)[/tex] is the mass of the object.
- [tex]\( g \)[/tex] is the acceleration due to gravity.
In this scenario:
- The mass ([tex]\( m \)[/tex]) of the object is 120 kg.
- The acceleration due to gravity ([tex]\( g \)[/tex]) on the moon is approximately 1.63 meters per second squared (m/s²).
Using the formula:
[tex]\[ F = 120 \ \text{kg} \times 1.63 \ \text{m/s}^2 \][/tex]
[tex]\[ F = 195.6 \ \text{N} \][/tex]
Therefore, the correct answer is:
C) 196 N
This is the force of gravity acting on the 120 kg object on the moon.
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