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The number of cars sold at a dealership over several weeks is given below.


14, 23, 31, 29, 33


What is the standard deviation for this set of population data?


Standard deviation: Sigma = StartRoot StartFraction (x 1 minus mu) squared + (x 2 minus mu) squared + ellipsis + (x N minus mu) squared Over N EndFraction EndRoot

6.9

12.4

15.4

47.2

The number of cars sold at a dealership over several weeks is given below 14 23 31 29 33 What is the standard deviation for

Answer :

The standard deviation for the set of population data given in the question is 6.9

How to determine the mean

  • Data = 14, 23, 31, 29, 33
  • Number of data (n) = 5
  • Summation of data = 14 + 23 + 31 + 29 + 33 = 130
  • Mean (μ) =?

Mean = summation of data / number

μ = 130 / 5

μ = 26

How to determine the standard deviation

  • Data = 14, 23, 31, 29, 33
  • Mean (μ) = 26
  • Number of data (n) = 5
  • Standard deviation (σ) =?

σ = √[[(x₁ - μ)² + (x₂ - μ)² + (x₃ - μ)² + (x₄ - μ)² + (x₅ - μ)²] / n]

σ = √[[(14 - 26)² + (23 - 26)² + (31 - 26)² + (29 - 26)² + (33 - 26)²] / 5]

σ = √[236 / 5}

σ = 6.9

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Rewritten by : Barada

Answer:

A. 6.9

Step-by-step explanation:

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