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Paul bought \(3 \frac{1}{3}\) pounds of bananas and apples. If he bought \(1 \frac{4}{5}\) pounds of apples, how many pounds of bananas did he buy?

Answer :

Paul bought 3 8/15 pounds of bananas.

Let's denote the pounds of apples Paul bought as A .

Given that Paul bought a total of [tex]\( 3 \frac{1}{3} \)[/tex] pounds of bananas and apples, and the pounds of apples is A , we can set up the equation:

[tex]\[ A + B = 3 \frac{1}{3} \][/tex]

Where B represents the pounds of bananas.

Given that Paul bought [tex]\( 1 \frac{4}{5} \)[/tex] pounds of apples, which is [tex]\( \frac{9}{5} \)[/tex] pounds, we can substitute this into the equation:

[tex]\[ \frac{9}{5} + B = 3 \frac{1}{3} \][/tex]

Now, let's solve for B :

[tex]\[ B = 3 \frac{1}{3} - \frac{9}{5} \][/tex]

To subtract these mixed numbers, we need to find a common denominator:

[tex]\[ B = \frac{16}{3} - \frac{9}{5} \][/tex]

Now, let's find a common denominator, which is 15 :

[tex]\[ B = \frac{16 \times 5}{3 \times 5} - \frac{9 \times 3}{5 \times 3} \][/tex]

[tex]\[ B = \frac{80}{15} - \frac{27}{15} \][/tex]

Now, we can subtract:

[tex]\[ B = \frac{80 - 27}{15} \][/tex]

[tex]\[ B = \frac{53}{15} \][/tex]

Now, we need to express [tex]\( \frac{53}{15} \)[/tex] as a mixed number:

[tex]\[ B = 3 \frac{8}{15} \][/tex]

Therefore, Paul bought [tex]\( 3 \frac{8}{15} \)[/tex] pounds of bananas.

The Correct question is:

Paul bought 3 1/3 pounds of bananas and apples. If he bought pounds of apples, 1 4/5 now many pounds of bananas did he buy?

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