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Assume the number of bacteria at time \( t \), in hours, is given by the following exponential function:

\[ N(t) = 500e^{0.04t} \]

Find the number of bacteria at time \( t = 0 \) and determine how many days it will take for the number of bacteria to reach 2000.

Answer :

Final answer:

The number of bacteria at time 0 is 500. It takes approximately 1.44 days for the number of bacteria to reach 2000.


Explanation:

The given exponential function for the number of bacteria at time t is: N(t) = 500e^(0.04t).

To find the number of bacteria at time 0, substitute t = 0 into the function:

N(0) = 500e^(0.04(0)) = 500e^0 = 500(1) = 500 bacteria.

To find how many days it takes for the number of bacteria to reach 2000, set N(t) = 2000 and solve for t:

2000 = 500e^(0.04t)

e^(0.04t) = 2000/500 = 4

Take the natural logarithm of both sides to isolate the exponent:

ln(e^(0.04t)) = ln(4)

0.04t = ln(4)

t = ln(4)/0.04

Using a calculator, t ≈ 34.66 hours or approximately 1.44 days.


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