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Answer :
To solve the problem, we need to find out how many games Annette's soccer team played last season.
According to the problem, this season's total number of games (15 games) is 7 games fewer than 2 times the number of games played last season. We can represent the situation with an equation and solve for the number of games played last season.
1. Let's call the number of games played last season [tex]\( x \)[/tex].
2. According to the problem, two times the number of games played last season, minus 7, equals 15. We can write this as:
[tex]\[
2x - 7 = 15
\][/tex]
3. To solve for [tex]\( x \)[/tex], first add 7 to both sides of the equation to get rid of the -7:
[tex]\[
2x - 7 + 7 = 15 + 7
\][/tex]
Simplifying this, we get:
[tex]\[
2x = 22
\][/tex]
4. Next, divide both sides of the equation by 2 to solve for [tex]\( x \)[/tex]:
[tex]\[
x = \frac{22}{2}
\][/tex]
[tex]\[
x = 11
\][/tex]
So, Annette's soccer team played 11 games last season.
According to the problem, this season's total number of games (15 games) is 7 games fewer than 2 times the number of games played last season. We can represent the situation with an equation and solve for the number of games played last season.
1. Let's call the number of games played last season [tex]\( x \)[/tex].
2. According to the problem, two times the number of games played last season, minus 7, equals 15. We can write this as:
[tex]\[
2x - 7 = 15
\][/tex]
3. To solve for [tex]\( x \)[/tex], first add 7 to both sides of the equation to get rid of the -7:
[tex]\[
2x - 7 + 7 = 15 + 7
\][/tex]
Simplifying this, we get:
[tex]\[
2x = 22
\][/tex]
4. Next, divide both sides of the equation by 2 to solve for [tex]\( x \)[/tex]:
[tex]\[
x = \frac{22}{2}
\][/tex]
[tex]\[
x = 11
\][/tex]
So, Annette's soccer team played 11 games last season.
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