College

We appreciate your visit to A 1 70 m long string has a standing wave with 2 00 loops at a frequency of 38 4 Hz What is the velocity. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!

A 1.70 m long string has a standing wave with 2.00 loops at a frequency of 38.4 Hz.

What is the velocity of the waves in the string?

[tex]v = \, ? \, \text{m/s}[/tex]

Answer :

To find the velocity of the waves in the string, we can follow these steps:

1. Understand the scenario: The string is 1.70 meters long and has a standing wave with 2 loops. A standing wave with 2 loops means there is one full wavelength on the string, because each loop represents half of a wavelength.

2. Calculate the wavelength: Since there are 2 loops forming one full wavelength on a 1.70-meter-long string, the wavelength is divided equally across the loops. Therefore, the wavelength is:

[tex]\[
\text{Wavelength} = \frac{\text{Length of the string}}{\text{Number of loops}} = \frac{1.70 \, \text{m}}{2} = 0.85 \, \text{m}
\][/tex]

3. Calculate the velocity of the waves: The velocity of waves can be calculated using the formula:

[tex]\[
\text{Velocity} = \text{Frequency} \times \text{Wavelength}
\][/tex]

Given that the frequency of the wave is 38.4 Hz, we can substitute the values to calculate the velocity:

[tex]\[
\text{Velocity} = 38.4 \, \text{Hz} \times 0.85 \, \text{m} = 32.64 \, \text{m/s}
\][/tex]

So, the velocity of the waves in the string is 32.64 meters per second.

Thanks for taking the time to read A 1 70 m long string has a standing wave with 2 00 loops at a frequency of 38 4 Hz What is the velocity. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!

Rewritten by : Barada