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Answer :
The solubility of NaCl at 30°C is 36.3 g/100 g of water. 108.9 g of NaCl is contained in a saturated solution that contains 300.0 grams of water
Explanation:
Usually, the term solubility refers to the quantity of solute which dissolves in a particular amount of solvent. Some of the substances that are soluble in aqueous are salts of Group IA, ammonium salts, acetates, nitrates.
Some salts might be insoluble in liquid and we call then as precipitates.
The solubility of NaCl at 30°C is 36.3 g, 100 g of water which means about 36.3 g of NaCl can be dissolved in 100g of water at 30°C
So, at the same temperature that is 30°C the number of grams of NaCl that can dissolve in 300g is
,
[tex]\frac{36,3 \mathrm{g} \text { of } \mathrm{NaCl}}{100 \mathrm{g} \text { of } \mathrm{H}_{2} \mathrm{O}}[/tex] = [tex]\frac{X g\ of\ N a C l}{300 g\ of\ H_{2} O}[/tex]
X g of NaCl =[tex]300 \mathrm{g} \text { of } \mathrm{H}_{2} \mathrm{O} \times \frac{36.3 \mathrm{g} \text { of } \mathrm{NaCl}}{100 \mathrm{g} \text { of } \mathrm{H}_{2} \mathrm{O}}[/tex]
Therefore, X g of NaCl = 108.9 g of NaCl
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Final answer:
In a saturated solution with 300.0 grams of water at 30°C, 108.9 grams of NaCl would be dissolved.
Explanation:
The solubility of NaCl at 30°C is 36.3 g per 100 g of water. To determine the mass of NaCl in a saturated solution with 300.0 grams of water, we need to perform a simple calculation based on proportionality. Since 36.3 grams of NaCl dissolve in 100 grams of water, we can multiply the amount of NaCl that can dissolve by 3 (because we have 300 grams of water which is three times the reference amount of 100 grams of water). Therefore, the mass of NaCl in a 300-gram saturated solution would be 36.3 g × 3 = 108.9 grams of NaCl.
