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A rocket is fired upward from some initial distance above the ground. Its height in feet, [tex]h[/tex], above the ground, [tex]t[/tex] seconds after it is fired, is given by the equation:

[tex]h = -16t^2 + 112t + 704[/tex].

1. What is the rocket's maximum height?
- 900 ft

2. How long does it take for the rocket to reach its maximum height?
- [tex]t = \square \, \text{sec}[/tex]

Answer :

To find the rocket's maximum height and the time it takes to reach that height, we need to analyze the given quadratic equation for the height of the rocket:

[tex]\[ h = -16t^2 + 112t + 704 \][/tex]

This equation is a quadratic in the form [tex]\( at^2 + bt + c \)[/tex], where:
- [tex]\( a = -16 \)[/tex]
- [tex]\( b = 112 \)[/tex]
- [tex]\( c = 704 \)[/tex]

The vertex of a parabola (which in this case opens downward since [tex]\( a < 0 \)[/tex]), gives the maximum point when the parabola opens downwards. The formula to find the time, [tex]\( t \)[/tex], at which the maximum height occurs is:

[tex]\[ t = -\frac{b}{2a} \][/tex]

Substituting the values of [tex]\( a \)[/tex] and [tex]\( b \)[/tex] into this formula, we get:

[tex]\[ t = -\frac{112}{2 \times -16} \][/tex]

[tex]\[ t = -\frac{112}{-32} \][/tex]

[tex]\[ t = 3.5 \][/tex]

Therefore, it takes [tex]\( 3.5 \)[/tex] seconds for the rocket to reach its maximum height.

Now, to find the maximum height, we substitute [tex]\( t = 3.5 \)[/tex] back into the original height equation:

[tex]\[ h = -16(3.5)^2 + 112(3.5) + 704 \][/tex]

This simplification gives a maximum height of:

[tex]\[ h = 900 \][/tex]

Thus, the rocket's maximum height is 900 feet, and it takes [tex]\( 3.5 \)[/tex] seconds to reach this height.

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