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Select the correct answer.

Each month, Barry makes three transactions in his checking account:
- He deposits [tex]$\$ 700$[/tex] from his paycheck.
- He withdraws [tex]$\$ 150$[/tex] to buy gas for his car.
- He withdraws [tex]$\$ 400$[/tex] for other expenses.

If his account balance is [tex]$1,900$[/tex] at the end of the 1st month, which recursive equation models Barry's account balance at the end of month [tex]n[/tex]?

A. [tex]f(1)=1,900[/tex]
[tex]f(n)=f(n-1)+700[/tex], for [tex]n \geq 2[/tex]

B. [tex]f(1)=1,900[/tex]
[tex]f(n)=f(n-1)+150[/tex], for [tex]n \geq 2[/tex]

C. [tex]f(1)=1,900[/tex]
[tex]f(n)=f(n-1)-150[/tex], for [tex]n \geq 2[/tex]

D. [tex]f(1)=1,900[/tex]
[tex]f(n)=150 \cdot f(n-1)[/tex], for [tex]n \geq 2[/tex]

Answer :

To solve this problem, we need to model Barry's checking account balance using a recursive equation based on the transactions he makes each month.

Here's a step-by-step explanation:

1. Initial Account Balance:
- At the end of the 1st month, Barry's account balance is [tex]$1,900.

2. Monthly Transactions:
- Barry deposits $[/tex]700 from his paycheck.
- He withdraws [tex]$150 for gas.
- He withdraws $[/tex]400 for other expenses.

3. Net Monthly Change:
- To find out how much Barry's balance changes each month, it's important to calculate the net effect of these transactions.
- Total Deposits: [tex]$700
- Total Withdrawals: $[/tex]150 (for gas) + [tex]$400 (for other expenses) = $[/tex]550
- Net Change in Balance: [tex]$700 (deposits) - $[/tex]550 (withdrawals) = $150

4. Recursive Equation:
- We start with an initial balance at the end of the 1st month: [tex]\( f(1) = 1,900 \)[/tex].
- For subsequent months [tex]\( n \geq 2 \)[/tex], the balance can be calculated using the previous month's balance (since it increases by the net change):
[tex]\[
f(n) = f(n-1) + 150
\][/tex]

By reviewing these calculations, we match them to the options given. The correct recursive equation that models Barry's account balance at the end of month [tex]\( n \)[/tex] is:

A.
[tex]\[ f(1) = 1,900 \][/tex]
[tex]\[ f(n) = f(n-1) + 150, \text{ for } n \geq 2 \][/tex]

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