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Answer :
Final answer:
The internal resistance of a battery can be calculated using Ohm’s Law (V = IR). In this scenario, with a battery of 12.0 V and current of 600 A, the internal resistance is calculated to be 0.02 Ohms.
Explanation:
This question is referring to Ohm’s law, which in its simplest form states: Voltage = Current x Resistance (V = IR). Here, voltage is 12.0 V (often referred to as the electromotive force or emf in a battery), and the current is 600 A (given as the 'cold-cranking' amps). We're tasked with finding the internal resistance denoted as ‘r’, which is the resistance within the battery itself.
Re-arranging Ohm's law to solve for 'r', we get r = V/I. Substituting the given values in we get r = 12.0 V / 600 A = 0.02 Ohms. Hence, the internal resistance of the battery is 0.02 Ohms.
Learn more about Ohm's Law here:
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