For an unconfined aquifer observed using two wells, the hydraulic conductivity is [tex]4.85 \text{ km/yr}[/tex]. The elevation reading at Station A is [tex]97.8 \text{ meters}[/tex], and at Station B, it is [tex]92.8 \text{ meters}[/tex]. The average depth of the aquifer is [tex]23.00 \text{ meters}[/tex]. Stations A and B are [tex]100 \text{ meters}[/tex] apart. Determine the flow through a section [tex]800 \text{ meters}[/tex] in length.

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prabhatrathi24se prabhatrathi24se · Answer 1 · 2024-03-24T23:50:13-04:00

The flow through a section of 800 meters in length in the unconfined aquifer is approximately 4,232 cubic meters per year.

To determine the flow through a section of 800 meters in length in an unconfined aquifer, we can use Darcy's law:

Q = K * A * (h1 - h2) / L

Where:

First, let's calculate the hydraulic gradient:

h1 - h2 = 97.8 - 92.8 = 5 meters

Next, let's calculate the cross-sectional area:

A = average depth * length = 23.00 * 800 = 18,400 square meters

Now, we can calculate the flow rate:

Q = 4.85 km/yr * 18,400 square meters * 5 meters / 100 meters = 4.85 * 18,400 * 5 / 100 = 4,232 cubic meters per year

Therefore, the flow through a section of 800 meters in length in the unconfined aquifer is approximately 4,232 cubic meters per year.

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