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Answer :
Answer:
The rotational kinetic energy = 7909.73 Joules
Explanation:The mass of the motorcycle, m = 9kg
The angular velocity, w = 137 rad/s
Inner radius, r = 0.280 m
Outer radius, R = 0.330 m
The rotational kinetic energy is calculated as:
[tex]KE_{\text{rot}}=\frac{m}{4}(r^2+R^2)w^2[/tex]Substitute m = 9, r = 0.280, R = 0.330, and w = 137 rad/s into the formula above
[tex]\begin{gathered} KE_{\text{rot}}=\frac{9}{4}(0.280^2+0.33^2)137^2 \\ KE_{\text{rot}}=\frac{9}{4}(0.1873)(18769) \\ KE_{\text{rot}}=7909.73\text{ }Joules\text{ } \end{gathered}[/tex]Thanks for taking the time to read Calculate the rotational kinetic energy of a 9 kg motorcycle wheel if its angular velocity is 137 rad s its inner radius is 0 280. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!
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