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Factor completely:

\[ -4s + 8 \]

\[ -4s + 8 = \]

\[ \square \]

Answer :

Sure! Let's solve the given expression step-by-step.

Given expression:
[tex]\[ -4s + 8 \][/tex]

#### Step 1: Identify the Greatest Common Factor (GCF)
First, we need to find the greatest common factor of the terms in the expression. Both terms, [tex]\(-4s\)[/tex] and [tex]\(8\)[/tex], share a factor of [tex]\(-4\)[/tex].

#### Step 2: Factor out the GCF
Next, we factor out [tex]\(-4\)[/tex] from each term in the expression:

[tex]\[ -4s + 8 = -4(s - 2) \][/tex]

Here’s how we get this:
- We can write [tex]\(-4s\)[/tex] as [tex]\(-4 \cdot s\)[/tex].
- We can write [tex]\(8\)[/tex] as [tex]\(-4 \cdot (-2)\)[/tex].

Putting it all together:
[tex]\[ -4s + 8 = -4(s - 2) \][/tex]

This means the common factor [tex]\(-4\)[/tex] is taken out, leaving us with the simplified term inside the parentheses.

So, the completely factored form of [tex]\(-4s + 8\)[/tex] is:
[tex]\[ \boxed{-4(s - 2)} \][/tex]

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Rewritten by : Barada