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Answer :
15 m/s for 10 sec; distance covered = (15 x 10) = 150 m
Second segment:
20 m/s for 20 sec; distance covered = (20 x 20) = 400 m
Third segment:
30 m/s for 15 sec; distrance covered = (30 x 15) = 450 m
Total time = (10s + 20s + 15s) = 45 sec
Total distance = (150m + 400m + 450m) = 1,000 m (1 km)
Average speed = (1,000 m) / (45 sec) = 22.22 m/s ...
Second segment:
20 m/s for 20 sec; distance covered = (20 x 20) = 400 m
Third segment:
30 m/s for 15 sec; distrance covered = (30 x 15) = 450 m
Total time = (10s + 20s + 15s) = 45 sec
Total distance = (150m + 400m + 450m) = 1,000 m (1 km)
Average speed = (1,000 m) / (45 sec) = 22.22 m/s ...
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Answer:
Explanation:
average speed=distance travelled/time taken
distance=speed*time
15*10=150 m
1200 m/min=20 m/s
0.17 minute=10.2 seconds
20*10.2=204 m
2500 cm/s=25 m/s
5000 milliseconds=5 seconds
25*5=125 m
125+150+204=479 m
10.2+5+10=25.2
479/25.2=19.0
