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Josiah invests [tex]\$360[/tex] into an account that accrues [tex]3\%[/tex] interest annually. Assuming no deposits or withdrawals are made, which equation represents the amount of money in Josiah's account, [tex]y[/tex], after [tex]x[/tex] years?

A. [tex]y = 360(1.3)^x[/tex]
B. [tex]y = 360(0.3)^x[/tex]
C. [tex]y = 360(0.03)^x[/tex]
D. [tex]y = 360(1.03)^x[/tex]

Answer :

To determine the equation that represents the amount of money in Josiah's account after a certain number of years, we need to think about how compound interest works.

Josiah invests [tex]$360 in an account with an annual interest rate of 3%. The formula for calculating the amount of money in an account with compound interest is:

\[ y = P(1 + r)^x \]

where:
- \( y \) is the amount of money after \( x \) years,
- \( P \) is the principal amount (initial amount), which is $[/tex]360 in this case,
- [tex]\( r \)[/tex] is the annual interest rate (expressed as a decimal), which is 3% or 0.03,
- [tex]\( x \)[/tex] is the number of years the money is invested for.

Plugging the given values into the formula, we have:

[tex]\[ y = 360(1 + 0.03)^x \][/tex]

This simplifies to:

[tex]\[ y = 360(1.03)^x \][/tex]

Therefore, the correct equation that represents the amount of money in Josiah's account after [tex]\( x \)[/tex] years is:

[tex]\[ y = 360(1.03)^x \][/tex]

This equation shows that the amount of money increases each year by 3%, applied to the total amount in the account at the start of that year.

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