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What is the density of an object with a mass of 5g that, when placed in a graduated cylinder, raises the volume of water from 30mL to 45mL?

Answer :

The density of the object is approximately 0.33 g/mL.

[tex]\text{Density} (\rho) = \frac{\text{Mass} (m)}{\text{Volume} (V)}[/tex]

Here, the mass [tex]m[/tex] of the object is given as 5 grams.

The volume [tex]V[/tex] can be found by the change in water level when the object is submerged in a graduated cylinder. It goes from 30 mL to 45 mL.

The volume of the object is:

[tex]V = 45 \text{ mL} - 30 \text{ mL} = 15 \text{ mL}[/tex]

Now, we can calculate the density:

[tex]\rho = \frac{5 \text{ g}}{15 \text{ mL}}[/tex]

Simplifying this, we get:

[tex]\rho = \frac{5}{15} \text{ g/mL} = \frac{1}{3} \text{ g/mL} \approx 0.33 \text{ g/mL}[/tex]

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