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A rectangular doorway has a temporary support beam across its diagonal. The height of the doorway is 2 times its width. If the beam across the diagonal is 14 feet, how wide is the doorway?

Answer :

Pythagoras' theorem, is a basic relationship between the three sides of a right triangle in Euclidean geometry. The width of the door is 6.26 ft or √(196/5)ft.

What is Pythagoras theorem?

The Pythagorean theorem, sometimes known as Pythagoras' theorem, is a basic relationship between the three sides of a right triangle in Euclidean geometry. The size of the square whose side is the hypotenuse is equal to the sum of the areas of the squares on the other two sides, according to this rule.

Given the length of the rectangular door is two times its width, therefore, the length and width of the rectangular door are,

Width = x

Length = 2x

Since the measure of the diagonal of the rectangular door is 14 feet, therefore, using the Pythagorus theorem we can write,

x² + (2x)² = 14²

x² + 4x² = 196

5x² = 196

x² = 196/5

x = 6.26099 ≈ 6.26ft

Hence, the width of the door is 6.26 ft or √(196/5)ft.

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Rewritten by : Barada

Answer:

The door has a width of 6.26 feet, with a height of 12.52 feet.

Step-by-step explanation:

You can solve this by taking two pieces of information we're given:

1) the diagonal size of the doorway is 14 feet

2) the height of the doorway twice its width

First lets describe the width and height using the diagonal length. We can do that with the Pythagorean theorem:

w² + h² = 14²

Now we can use the relationship between the width and height to eliminate one variable:

w² + (2w)² = 14²

w² + 4w² = 14²

5w² = 196

w² = 39.2

w ≈ 6.26

So the door has a width of 6.26 feet, with a height of double that, 12.52 feet.