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Determine the depth of a cubical aerated grit chamber necessary to treat a flow of 6.2 MGD if the design hydraulic retention time is 3 minutes.

Note: MGD = million gallons per day, 1 ft³ = 7.48 gallons.

Answer :

Final answer:

The depth of the cubical aerated grit chamber necessary to treat a flow of 6.2 MGD with a design hydraulic retention time of 3 minutes is approximately 140.9 ft.

Explanation:

To determine the depth of a cubical aerated grit chamber, we need to use the given flow rate and design hydraulic retention time. First, let's convert the flow rate from MGD to ft3/min:

1 MGD = 1,000,000 gallons/day = 1,000,000/7.48 ft3/day = 133,689.84 ft3/day

6.2 MGD = 6.2 * 133,689.84 ft3/day = 828,932.7288 ft3/day

Next, we need to calculate the volume of the chamber:

Volume = Flow rate * Retention time

Volume = 828,932.7288 ft3/day * 3 min = 2,486,798.1864 ft3

Since the chamber is cubical, all sides have the same length. Let's assume the side length of the chamber is 'x' ft. The volume of a cube is given by:

Volume = x3

Equating the two volume equations, we have:

x3 = 2,486,798.1864 ft3

Taking the cube root of both sides, we find:

x = 140.9 ft

Therefore, the depth of the cubical aerated grit chamber necessary to treat a flow of 6.2 MGD with a design hydraulic retention time of 3 minutes is approximately 140.9 ft.

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