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Answer :
To find the stopping distance using the given function [tex]\( D(F) = 2F + 115 \)[/tex], we need to substitute different values of [tex]\( F \)[/tex] (the air temperature in degrees Fahrenheit) into the function. Here is how you can calculate each value step-by-step:
1. For [tex]\( D(0) \)[/tex]:
[tex]\[
D(0) = 2 \times 0 + 115 = 0 + 115 = 115
\][/tex]
So, the stopping distance when the temperature is 0 degrees Fahrenheit is 115.
2. For [tex]\( D(-30) \)[/tex]:
[tex]\[
D(-30) = 2 \times (-30) + 115 = -60 + 115 = 55
\][/tex]
Therefore, the stopping distance at -30 degrees Fahrenheit is 55.
3. For [tex]\( D(11) \)[/tex]:
[tex]\[
D(11) = 2 \times 11 + 115 = 22 + 115 = 137
\][/tex]
Hence, when the temperature is 11 degrees Fahrenheit, the stopping distance is 137.
In summary:
- [tex]\( D(-30) = 55 \)[/tex]
- [tex]\( D(11) = 137 \)[/tex]
These are the stopping distances for the respective temperatures.
1. For [tex]\( D(0) \)[/tex]:
[tex]\[
D(0) = 2 \times 0 + 115 = 0 + 115 = 115
\][/tex]
So, the stopping distance when the temperature is 0 degrees Fahrenheit is 115.
2. For [tex]\( D(-30) \)[/tex]:
[tex]\[
D(-30) = 2 \times (-30) + 115 = -60 + 115 = 55
\][/tex]
Therefore, the stopping distance at -30 degrees Fahrenheit is 55.
3. For [tex]\( D(11) \)[/tex]:
[tex]\[
D(11) = 2 \times 11 + 115 = 22 + 115 = 137
\][/tex]
Hence, when the temperature is 11 degrees Fahrenheit, the stopping distance is 137.
In summary:
- [tex]\( D(-30) = 55 \)[/tex]
- [tex]\( D(11) = 137 \)[/tex]
These are the stopping distances for the respective temperatures.
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