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Answer :
Given:
[tex]\begin{gathered} Total-table=60 \\ round-table=38 \\ window-side-table=13 \\ round-table(window-side)=6 \end{gathered}[/tex]To Determine: The probability that a customer will be seated at a round table or by the window
Solution
Probability is a ratio of the number of favorable outcomes to the number of possible outcomes of the experiment
[tex]Probability=\frac{Number(outcome)}{Number(Possible-outcome)}[/tex][tex]\begin{gathered} P(round-table)=\frac{38}{60} \\ P(window)=\frac{13}{60} \\ P(round-window)=\frac{6}{60} \end{gathered}[/tex]The probability that a customer will be seated at a round table or by the window would be
[tex]\begin{gathered} P(round-table,or,window)=P(round)+P(window)-P(round-window) \\ =\frac{38}{60}+\frac{13}{60}-\frac{6}{60} \\ =\frac{38+13-6}{60} \\ =\frac{51-6}{60} \\ =\frac{45}{60} \end{gathered}[/tex]Hence, the probability that a customer will be seated at a round table or by the window is 45/60
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