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What is the remainder in the synthetic division problem below?

[tex]
\[
\begin{array}{c|ccc}
1 & 1 & 2 & -3 \\
\hline
\end{array}
\]
[/tex]

Answer :

Sure! Let's go through the process of synthetic division to find the remainder.

### Synthetic Division Steps:

1. Identify the Divisor:
- In synthetic division, the divisor is usually in the form [tex]\( x - c \)[/tex]. Here, we've assumed the divisor is [tex]\( x - 1 \)[/tex], which means [tex]\( c = 1 \)[/tex].

2. Set Up Coefficients:
- Write down the coefficients of the dividend polynomial. In this case, the coefficients are 1, 2, and -3.

3. Perform Synthetic Division:
- Start by bringing down the leading coefficient (which is 1) to the bottom row.
- Multiply this number by the divisor root ([tex]\( c=1 \)[/tex]) and write the result under the next coefficient.
- Add the current column and write the result below the line.
- Repeat the multiply and add steps for the remaining coefficients.

4. Determine the Remainder:
- The last number at the bottom is the remainder.

### Work Through the Example:

- Coefficients: [tex]\( [1, 2, -3] \)[/tex]

#### Step-by-Step Process:

- Step 1: Bring down the 1 (the leading coefficient).
- New row: [tex]\([1]\)[/tex]

- Step 2: Multiply 1 (brought down) by 1 (the root of the divisor) and add to the next coefficient (2).
- Calculation: [tex]\( 1 \times 1 + 2 = 3 \)[/tex]
- Update row: [tex]\([1, 3]\)[/tex]

- Step 3: Multiply 3 by 1 (the root of the divisor) and add to the next coefficient (-3).
- Calculation: [tex]\( 3 \times 1 + (-3) = 0 \)[/tex]
- Update row: [tex]\([1, 3, 0]\)[/tex]

- Remainder: The last value in the row is 0.

Therefore, the remainder in the synthetic division is 0.

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