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Which statement is an example of the symmetric property of congruence?

A. [tex]\( \angle KLM \cong \angle KLM \)[/tex]
B. If [tex]\( \angle KLM \cong \angle PQR \)[/tex], then [tex]\( \angle PQR \cong \angle STU \)[/tex].
C. If [tex]\( \angle KLM \cong \angle PQR \)[/tex], then [tex]\( \angle PQR \cong \angle KLM \)[/tex].
D. If [tex]\( \angle KLM \cong \angle PQR \)[/tex], and [tex]\( \angle PQR \cong \angle STU \)[/tex], then [tex]\( \angle KLM \cong \angle STU \)[/tex].

Answer :

Sure! Let's understand what the symmetric property of congruence is and how it applies to the provided options.

The symmetric property of congruence is a fundamental property in geometry. It states that if one figure is congruent to another, then the second figure is congruent to the first. In other words, if [tex]\( A \cong B \)[/tex], then [tex]\( B \cong A \)[/tex].

Now let's analyze each option:

A. [tex]\( AKLM \cong AKLM \)[/tex] - This is a tautology, meaning a shape is congruent to itself. It doesn't demonstrate the symmetric property.

B. If [tex]\( AKLM \cong APQR \)[/tex], then [tex]\( APQR = ASTU \)[/tex] - This describes a different concept other than symmetry, possibly grouping toward transitive property if further reasoning is allowed, which involves a third element.

C. If [tex]\( AKLM \cong APQR \)[/tex], then [tex]\( APQR \cong AKLM \)[/tex] - This is precisely the definition of the symmetric property of congruence. It states that the congruence relationship works both ways between two figures.

D. If [tex]\( AKLM \cong APQR \)[/tex], and [tex]\( APQR \cong ASTU \)[/tex], then [tex]\( AKLM \cong ASTU \)[/tex] - This is an example of the transitive property, not the symmetric property. The transitive property involves a third element to link congruence.

Therefore, the statement that exemplifies the symmetric property of congruence is option C: "If [tex]\( AKLM \cong APQR \)[/tex], then [tex]\( APQR \cong AKLM \)[/tex]."

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