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Answer :
Sure! Let's solve the problem step-by-step.
The question asks us to find the equivalent unit for [tex]\( 10^{-6} \)[/tex] liters (L).
To solve this, we need to understand the relationship between liters and the smaller units.
1. Microliters ([tex]\(\mu\)[/tex]L):
- 1 liter (L) is equivalent to [tex]\(10^6\)[/tex] microliters ([tex]\(\mu\)[/tex]L).
- To find the equivalent of [tex]\(10^{-6}\)[/tex] liters, we convert it to microliters ([tex]\(\mu\)[/tex]L).
- Therefore, [tex]\(10^{-6}\)[/tex] liters is equal to 1 microliter ([tex]\(\mu\)[/tex]L), because:
[tex]\[
10^{-6} \text{ L} = \frac{10^{-6} \text{ L}}{10^{-6} \text{ L}/\mu\text{L}} = 1 \mu\text{L}
\][/tex]
2. Other units (to verify):
- Milliliters (mL): 1 liter (L) is [tex]\(10^3\)[/tex] milliliters (mL), so [tex]\(10^{-6} \text{ L} = 10^{-6} \times 10^3 \text{ mL} = 10^{-3} \text{ mL} = 0.001 \text{ mL}\)[/tex].
- Picoliters (pL): 1 liter (L) is [tex]\(10^{12}\)[/tex] picoliters (pL), so [tex]\(10^{-6} \text{ L} = 10^{-6} \times 10^{12} \text{ pL} = 10^6 \text{ pL}\)[/tex].
- Deciliters (dL): 1 liter (L) is [tex]\(10^1\)[/tex] deciliters (dL), so [tex]\(10^{-6} \text{ L} = 10^{-6} \times 10^1 \text{ dL} = 10^{-5} \text{ dL} = 0.00001 \text{ dL}\)[/tex].
After these conversions, it's clear that the equivalent unit for [tex]\(10^{-6}\)[/tex] liters is:
[tex]\[ 1 \mu\text{L} \][/tex]
So, the correct selection is:
[tex]\[
1 \mu\text{L}
\][/tex]
The question asks us to find the equivalent unit for [tex]\( 10^{-6} \)[/tex] liters (L).
To solve this, we need to understand the relationship between liters and the smaller units.
1. Microliters ([tex]\(\mu\)[/tex]L):
- 1 liter (L) is equivalent to [tex]\(10^6\)[/tex] microliters ([tex]\(\mu\)[/tex]L).
- To find the equivalent of [tex]\(10^{-6}\)[/tex] liters, we convert it to microliters ([tex]\(\mu\)[/tex]L).
- Therefore, [tex]\(10^{-6}\)[/tex] liters is equal to 1 microliter ([tex]\(\mu\)[/tex]L), because:
[tex]\[
10^{-6} \text{ L} = \frac{10^{-6} \text{ L}}{10^{-6} \text{ L}/\mu\text{L}} = 1 \mu\text{L}
\][/tex]
2. Other units (to verify):
- Milliliters (mL): 1 liter (L) is [tex]\(10^3\)[/tex] milliliters (mL), so [tex]\(10^{-6} \text{ L} = 10^{-6} \times 10^3 \text{ mL} = 10^{-3} \text{ mL} = 0.001 \text{ mL}\)[/tex].
- Picoliters (pL): 1 liter (L) is [tex]\(10^{12}\)[/tex] picoliters (pL), so [tex]\(10^{-6} \text{ L} = 10^{-6} \times 10^{12} \text{ pL} = 10^6 \text{ pL}\)[/tex].
- Deciliters (dL): 1 liter (L) is [tex]\(10^1\)[/tex] deciliters (dL), so [tex]\(10^{-6} \text{ L} = 10^{-6} \times 10^1 \text{ dL} = 10^{-5} \text{ dL} = 0.00001 \text{ dL}\)[/tex].
After these conversions, it's clear that the equivalent unit for [tex]\(10^{-6}\)[/tex] liters is:
[tex]\[ 1 \mu\text{L} \][/tex]
So, the correct selection is:
[tex]\[
1 \mu\text{L}
\][/tex]
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