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Answer :
Certainly! Let's work through each scenario step-by-step.
### Scenario 1: Ww x ww
In this scenario, we're crossing two organisms: one with a heterozygous genotype (Ww) and another with a homozygous recessive genotype (ww).
Here's the Punnett square representation for this cross:
1. W from Ww and w from ww, resulting in Ww
2. w from Ww and w from ww, resulting in ww
3. W from Ww and w from ww, resulting in Ww
4. w from Ww and w from ww, resulting in ww
Now, let's look at the probabilities:
- Two of the four possible outcomes are Ww, which are heterozygous.
- The probability that an offspring will be heterozygous Ww is 2 out of 4, or 0.5, which is 50%.
### Scenario 2: Ww x WW
In this scenario, we're crossing a heterozygous genotype (Ww) with a homozygous dominant genotype (WW).
Here's the Punnett square representation for this cross:
1. W from Ww and W from WW, resulting in WW
2. w from Ww and W from WW, resulting in Ww
3. W from Ww and W from WW, resulting in WW
4. w from Ww and W from WW, resulting in Ww
For this setup, let's look at the possibilities:
- All four possible outcomes (WW, Ww, WW, Ww) result in either homozygous dominant (WW) or heterozygous (Ww).
- The probability of having a homozygous recessive (ww) offspring is 0 out of 4, or 0.0, which is 0%.
Thus, the probabilities are:
- A 50% chance (0.5) of getting a heterozygous (Ww) offspring in the first scenario.
- A 0% chance (0.0) of getting a homozygous recessive (ww) offspring in the second scenario.
### Scenario 1: Ww x ww
In this scenario, we're crossing two organisms: one with a heterozygous genotype (Ww) and another with a homozygous recessive genotype (ww).
Here's the Punnett square representation for this cross:
1. W from Ww and w from ww, resulting in Ww
2. w from Ww and w from ww, resulting in ww
3. W from Ww and w from ww, resulting in Ww
4. w from Ww and w from ww, resulting in ww
Now, let's look at the probabilities:
- Two of the four possible outcomes are Ww, which are heterozygous.
- The probability that an offspring will be heterozygous Ww is 2 out of 4, or 0.5, which is 50%.
### Scenario 2: Ww x WW
In this scenario, we're crossing a heterozygous genotype (Ww) with a homozygous dominant genotype (WW).
Here's the Punnett square representation for this cross:
1. W from Ww and W from WW, resulting in WW
2. w from Ww and W from WW, resulting in Ww
3. W from Ww and W from WW, resulting in WW
4. w from Ww and W from WW, resulting in Ww
For this setup, let's look at the possibilities:
- All four possible outcomes (WW, Ww, WW, Ww) result in either homozygous dominant (WW) or heterozygous (Ww).
- The probability of having a homozygous recessive (ww) offspring is 0 out of 4, or 0.0, which is 0%.
Thus, the probabilities are:
- A 50% chance (0.5) of getting a heterozygous (Ww) offspring in the first scenario.
- A 0% chance (0.0) of getting a homozygous recessive (ww) offspring in the second scenario.
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