Answer :

The general solution of the given differential equation is:

y = (1/7) + C * [tex]exp(-x^7)[/tex]

The exponential of the integral of the coefficient of y, in this case 7x6, provides the integrating factor. The integrating factor is given by the exponential of the integral of the coefficient of y, which in this case is 7x⁶.

The integrating factor is therefore exp(∫ 7x⁶ dx), which can be calculated as exp(x⁷/7).

Multiplying both sides of the differential equation by the integrating factor, we have:

exp(x⁷/7) * y' + 7x⁶ * exp(x⁷/7) * y = x⁶ * exp(x⁷/7)

Using the product rule on the left side, we can rewrite the equation as:

d/dx (exp(x⁷/7) * y) = x⁶ * exp(x⁷/7)

Integrating both sides with respect to x, we get:

exp(x⁷/7) * y = ∫ x⁶ * exp(x⁷/7) dx

The integral on the right side can be solved using integration by parts. Let's denote u = x⁶ and dv = exp(x⁷/7) dx. Then, du = 6x⁵ dx and v = 7/7 * exp(x⁷/7) = exp(x⁷/7).

Using the formula for integration by parts:

∫ u dv = uv - ∫ v du

We have:

∫ x⁶ * exp(x⁷/7) dx = x⁶ * exp(x⁷/7) - ∫ exp(x⁷/7) * 6x⁵ dx

Simplifying the integral on the right side, we obtain:

∫ exp(x⁷/7) * 6x⁵ dx = 6 * ∫ x⁵ * exp(x⁷/7) dx

We can apply integration by parts again to this integral, with u = x⁵ and dv = exp(x⁷/7) dx.

Continuing this process, we will eventually reach an integral of the form ∫ exp(x⁷/7) dx, which can be expressed in terms of special functions called exponential integrals.

Once we have the value of this integral, we can substitute it back into the expression for the integral of x⁶ * exp(x⁷/7) dx.

Finally, we divide both sides of the equation by exp(x⁷/7) and solve for y:

y = (1/exp(x⁷/7)) * (∫ x⁶ * exp(x⁷/7) dx)

The resulting expression will give the general solution to the given differential equation.

To solve this linear first-order ordinary differential equation, we can use an integrating factor. The integral of the coefficient of y's exponential integral, in this case 7x⁶, provides the integrating factor.

The integrating factor is therefore exp(∫ 7x⁶ dx), which can be calculated as exp((7/7) * x⁷) = exp(x⁷).

Multiplying both sides of the differential equation by the integrating factor, we have:

exp(x⁷) * y' + 7x⁶ * exp(x⁷) * y = x⁶ * exp(x⁷)

We can rewrite this equation as follows:

d/dx (exp(x⁷) * y) = x⁶ * exp(x⁷)

Integrating both sides with respect to x, we get:

exp(x⁷) * y = ∫ x⁶ * exp(x⁷) dx

To evaluate this integral, we can make a substitution. Let's substitute u = x⁷, then du = 7x⁶ dx.

The integral becomes:

(1/7) ∫ exp(u) du = (1/7) * exp(u) + C = (1/7) * exp(x⁷) + C

Now, dividing both sides of the equation by exp(x⁷), we have:

y = (1/7) + C * exp(-x⁷)

Therefore, the general solution of the given differential equation is:

y = (1/7) + C * exp(-x⁷)

where C is an arbitrary constant.

To know more about integration follow the given link:

https://brainly.com/question/30094386

#SPJ4

Thanks for taking the time to read Find the general solution of the given differential equation y 7x 6y x 6. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!

Rewritten by : Barada