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A given reaction has an energy difference between reactants and products [tex](\Delta H)[/tex] of [tex]-23.7 \, \text{kJ/mol}[/tex], and a forward activation energy [tex](A_E)[/tex] of [tex]27.9 \, \text{kJ/mol}[/tex]. Which of the following are possible values of [tex]\Delta H[/tex] and [tex]A_E[/tex] for the forward reaction in the presence of a catalyst? Select all that apply.

A. [tex]\Delta H = -9.27 \, \text{kJ/mol}[/tex] and [tex]A_E = 50.4 \, \text{kJ/mol}[/tex]

B. [tex]\Delta H = -12.1 \, \text{kJ/mol}[/tex] and [tex]A_E = 10.3 \, \text{kJ/mol}[/tex]

C. [tex]\Delta H = -43 \, \text{kJ/mol}[/tex] and [tex]A_E = 50.4 \, \text{kJ/mol}[/tex]

D. [tex]\Delta H = -23.7 \, \text{kJ/mol}[/tex] and [tex]A_E = 21.2 \, \text{kJ/mol}[/tex]

E. [tex]\Delta H = -23.7 \, \text{kJ/mol}[/tex] and [tex]A_E = 99.1 \, \text{kJ/mol}[/tex]

F. [tex]\Delta H = -23.7 \, \text{kJ/mol}[/tex] and [tex]A_E = 10.3 \, \text{kJ/mol}[/tex]

Answer :

To solve this problem, it's important to understand the role of a catalyst in a chemical reaction. A catalyst speeds up the reaction by lowering the activation energy, but it does not affect the overall energy change of the reaction ([tex]\(\Delta H\)[/tex]).

Here's how to evaluate the possible values for [tex]\(\Delta H\)[/tex] and [tex]\(A_E\)[/tex] with a catalyst involved:

1. Understand the given values:
- The energy difference between reactants and products without a catalyst ([tex]\(\Delta H\)[/tex]) is [tex]\(-23.7 \text{ kJ/mol}\)[/tex].
- The forward activation energy without a catalyst ([tex]\(A_E\)[/tex]) is [tex]\(27.9 \text{ kJ/mol}\)[/tex].

2. Recognize catalyst effects:
- A catalyst does not change the energy difference between reactants and products, so [tex]\(\Delta H\)[/tex] remains [tex]\(-23.7 \text{ kJ/mol}\)[/tex] when a catalyst is present.
- A catalyst lowers the activation energy required for the reaction.

3. Evaluate each option:
- For the pair [tex]\(\Delta H = -9.27 \text{ kJ/mol}\)[/tex] and [tex]\(A_E = 50.4 \text{ kJ/mol}\)[/tex]: [tex]\(\Delta H\)[/tex] does not match the required [tex]\(-23.7 \text{ kJ/mol}\)[/tex]. Hence, it is not possible.
- For the pair [tex]\(\Delta H = -12.1 \text{ kJ/mol}\)[/tex] and [tex]\(A_E = 10.3 \text{ kJ/mol}\)[/tex]: [tex]\(\Delta H\)[/tex] is incorrect.
- For the pair [tex]\(\Delta H = -43 \text{ kJ/mol}\)[/tex] and [tex]\(A_E = 50.4 \text{ kJ/mol}\)[/tex]: [tex]\(\Delta H\)[/tex] is incorrect.
- For the pair [tex]\(\Delta H = -23.7 \text{ kJ/mol}\)[/tex] and [tex]\(A_E = 21.2 \text{ kJ/mol}\)[/tex]: [tex]\(\Delta H\)[/tex] is correct and [tex]\(A_E\)[/tex] is lower than the original [tex]\(27.9 \text{ kJ/mol}\)[/tex], so this is valid.
- For the pair [tex]\(\Delta H = -23.7 \text{ kJ/mol}\)[/tex] and [tex]\(A_E = 99.1 \text{ kJ/mol}\)[/tex]: [tex]\(\Delta H\)[/tex] is correct, but [tex]\(A_E\)[/tex] is higher, not lower, so this is incorrect.
- For the pair [tex]\(\Delta H = -23.7 \text{ kJ/mol}\)[/tex] and [tex]\(A_E = 10.3 \text{ kJ/mol}\)[/tex]: [tex]\(\Delta H\)[/tex] is correct and [tex]\(A_E\)[/tex] is lower, making this choice valid.

So, the possible values for [tex]\(\Delta H\)[/tex] and [tex]\(A_E\)[/tex] for the forward reaction in the presence of a catalyst are:

- [tex]\(\Delta H = -23.7 \text{ kJ/mol}\)[/tex] and [tex]\(A_E = 21.2 \text{ kJ/mol}\)[/tex]
- [tex]\(\Delta H = -23.7 \text{ kJ/mol}\)[/tex] and [tex]\(A_E = 10.3 \text{ kJ/mol}\)[/tex]

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